Arriving at Calculations
1. How does NRCan arrive at the fuel, CO2 and dollar amounts quoted in the messages for three minutes of idling?
Per Vehicle Calculation:
Idle time per day = 3 min per day = 0.050 hours per day
Idle fuel flow (L/hr) = (idle fuel flow factorFootnote 12 ) × (engine displacement in litresFootnote 13 )
= (0.6 litres/hr per litre of engine displacement) × (3 litres)
= 1.8 litres per hour
Idle fuel use (L/year) = (idle fuel flow) × (idle time per day) × (days in year)
= 1.8 L/hr × 0.050 hr/day × 365 days/year
= 32.85 litres per year
Idle CO2 emissions (kg/year) = (idle fuel use) × (CO2 emission factor)Footnote 14
= 32.85 L/yr) × 2.3 kg/L
= 75.56 kg per year
Idle fuel cost ($/year) = (idle fuel use) × (cost of fuel)
= 32.85 L/yr × $1 per litre (assumed)
= $32.85 per year
Canada-Wide Savings – Per Year based on the year 2007:
Fuel savings (litres/year) = (fuel use per vehicle) × (number of vehicles)
= 32.85 L/year × 19,198,960 vehiclesFootnote 15
= 630,685,836 L/year
= 630 million litres per year
CO2 savings (tonnes) = (CO2 emissions per vehicle) × (number of vehicles)
= 75.56 kg/year × 19,198,960 vehiclesFootnote 16
= 1,450,577,423 kg/year
= 1,450,577 tonnes/year = 1.4 million tonnes per year
Cost savings ($/year) = (fuel cost per vehicle) × (number of vehicles)
= $ 32.85 × 19,198,960 vehicles Footnote 17
= $ 630,685,836 per year
= $ 630 million per year
Number of vehicles off road = (fuel savings) ÷ (annual fuel use per vehicle)
= 630,685,836 l/year ÷ 1,950 L/year
= 323,429 vehicles
= 320,000 vehicles
Canada-Wide Savings - Per Day:
The following values were calculated using the Canada-wide savings per year and dividing by 365 days:
- Daily fuel savings: 1.7 million litres per day
- Daily CO2 savings: 3,974 tonnes per day
- Daily cost savings: $1.7 million per day
2. My vehicle's engine size and idle times are different than the examples in question 1. Can you tell me what my fuel use and CO2 emissions are per year?
The following table provides data for three types of engines based on number of cylinders for idling time to a maximum of 10 minutes per day. The calculation method for each table value is the same as that for question 1.
Idle Time | Fuel Use (litres per year) | CO 2 Emissions ( kg per year) | ||||
---|---|---|---|---|---|---|
(minutes per day) | 1 litre Engine | 3 litre Engine | 5 litre Engine | 1 litre Engine | 3 litre Engine | 5 litre Engine |
1 | 4 | 11 | 18 | 9 | 25 | 41 |
2 | 7 | 22 | 37 | 16 | 51 | 85 |
3 | 11 | 33 | 55 | 25 | 76 | 126 |
4 | 15 | 44 | 73 | 34 | 101 | 168 |
5 | 18 | 55 | 91 | 41 | 126 | 209 |
6 | 22 | 66 | 110 | 51 | 152 | 253 |
7 | 26 | 77 | 128 | 60 | 177 | 294 |
8 | 29 | 88 | 146 | 67 | 202 | 336 |
9 | 33 | 99 | 164 | 76 | 228 | 377 |
10 | 37 | 110 | 183 | 85 | 253 | 421 |
3. How can a vehicle produce about three times its own weight in CO2 each year?
Ratio = (annual fuel use per vehicle × CO2 emission factor) ÷ (average vehicle weight = (1,950 L × 2.3 kg CO2/l) ÷ 1,450 kg
= 4,485 kg ÷ 1,450 kg
= 3.093
= 3 times its own weight
4. How does idling for just 10 minutes use over 1 cup of fuel for a vehicle with a 3 litre engine and over 2 cups of fuel for a vehicle with a 5 litre engine?
Idle time = 10 minutes = 0.166 hours
For a 3 litre engine:
Fuel use
= (idle time) × (idle fuel flow factor Footnote 18) × (engine displacement) = (0.166 hr) × (0.6 L/hr per litre of engine displacement) × (3.0 litres)
= (0.166 hr) × (1.8 L/hour)
= 300 ml
= 300 ml ÷ 236 ml per cup
= 1.3 cups
For a 5 litre engine
Fuel use = (idle time) × (idle fuel flow factor Footnote 19) × (engine displacement)
= (0.166 hr) × (0.6 L/hr per litre of engine displacement) × (5.0 litres)
= (0.166 hr) × (3.0 L/hour)
= 500 ml
= 500 ml ÷ 236 ml per cup
= 2.1 cups
Note: 1 cup = 8 fluid ounces = 236 millilitres
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